e_221001
plain-language theorem explainer
For the six-index slot (2,2,1,0,0,1) on Fin 4, the folded coupling numerator equals eight times the closed-form kernel value. Gravity analysts cite it when discharging one cell of the 4D Regge midpoint M2TT identity. The proof is a single kernel decide on concrete integers.
Claim. With indices in $\{0,1,2,3\}$, the coupling numerator at $(2,2,1,0,0,1)$ satisfies $m_2^{\mathrm{num}}(2,2,1,0,0,1)=8\,Z_{\mathrm{ex}}(2,2,1,0,0,1)$, where $m_2^{\mathrm{num}}$ is the fold of local contributions and $Z_{\mathrm{ex}}$ is the explicit integer kernel.
background
In the 4D Regge midpoint analysis, two integer-valued maps on six Fin-4 indices are compared. The numerator $m_2^{\mathrm{num}}$ accumulates every local contribution from a fixed coupling list by a left fold starting at zero. The companion $Z_{\mathrm{ex}}$ is an explicit case table of small integers (entries such as $4$, $-2$, and so on) that is meant to be the closed form of that sum, up to a universal factor of eight.
This module is chunk 10 of a 256-way split of the kernel: each declaration pins one concrete six-tuple so the global identity can be reassembled by exhaustive fin-cases. The local setting is pure integer arithmetic on the discrete index cube; no continuum limit is taken here.
proof idea
One-line proof by decide. Lean reduces both sides at the concrete indices $(2,2,1,0,0,1)$: the fold that defines the numerator and the matching clause of the explicit kernel, then checks the integer equality $n=8z$ in the kernel.
why it matters
The parent theorem m2Num_eq_eight_explicitZ states the identity for every six-tuple and proves it by nested fin-cases; each case lands on a chunk lemma of this form. Without the cell-by-cell certificates the assemble step cannot close. In the broader gravity stack this identity is bookkeeping for the exact midpoint M2TT kernel in four dimensions, a discrete curvature ingredient used when matching Regge-type actions to continuum limits. It does not itself invoke the RS forcing chain (T5–T8) or the J-cost, but it sits inside the gravity analysis that those foundations eventually constrain.
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