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def definition def or abbrev high

cert_tau

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cert_tau defines the ResidueCert for the tau lepton with rational bounds 13.89 to 13.90. Mass-spectrum auditors in Recognition Science cite it when checking lepton clustering against the integer-rung prediction near F(1332). The definition directly instantiates the ResidueCert record and applies norm_num to discharge the bound inequality.

claimThe tau residue certificate is the structure with fermion component $f = $ tau lepton, lower bound $lo = 13.89$, upper bound $hi = 13.90$, and the inequality $lo ≤ hi$ proved by normalization.

background

ResidueCert is the structure with fields f : Fermion, lo : ℚ, hi : ℚ and lo_le_hi : lo ≤ hi. It packages numerical bounds on the gap function at the anchor scale. From AnchorPolicy, F(Z) := log(1 + Z/φ) / log(φ) is the display function that these certificates are designed to bound. The module supplies audit payloads obtained by RG transport of experimental masses; lepton certificates are expected to cluster near the theoretical value F(1332) ≈ 13.95.

proof idea

One-line record construction that supplies the fermion tau, the explicit rationals 1389/100 and 1390/100, and invokes the norm_num tactic to prove the inequality between them.

why it matters in Recognition Science

cert_tau is collected into leptonCerts together with cert_e and cert_mu. That list verifies the integer-rung model for leptons against the anchor axiom in AnchorPolicy. Within the Recognition Science chain it supplies concrete data for the phi-ladder mass formula and the T5 J-uniqueness step that forces the self-similar fixed point.

scope and limits

Lean usage

example : cert_tau ∈ leptonCerts := by simp [leptonCerts]

formal statement (Lean)

  76def cert_tau : ResidueCert := {

proof body

Definition body.

  77  f := tau,
  78  lo := 1389/100,  -- 13.89
  79  hi := 1390/100,  -- 13.90
  80  lo_le_hi := by norm_num
  81}
  82
  83/-! ## Quark Certificates
  84    Quarks show the Quarter-Ladder vs Integer-Rung tension.
  85    Theoretical target: F(276) ≈ 10.71 (up) or F(24) ≈ 5.74 (down)
  86-/
  87

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