theorem
proved
boson_symmetric_wavefunction
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IndisputableMonolith.QFT.SpinStatistics on GitHub at line 201.
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198 simp [exchangeSymmetryFromSpin, h]
199
200/-- **THEOREM**: Bosons have symmetric wavefunctions. -/
201theorem boson_symmetric_wavefunction (s : Spin) (h : s.isInteger) :
202 exchangeSymmetryFromSpin s = ExchangeSymmetry.symmetric := by
203 simp [exchangeSymmetryFromSpin]
204 intro h'
205 exact absurd (And.intro h h') (Spin.int_half_exclusive s)
206
207/-! ## Pauli Exclusion Principle -/
208
209/-- **THEOREM (Pauli Exclusion)**: Fermions cannot occupy the same quantum state.
210
211 This follows from antisymmetry: if two fermions are in the same state,
212 the wavefunction ψ(1,1) = -ψ(1,1), which implies ψ(1,1) = 0.
213
214 Proof: From x = -x, add x to both sides: 2x = 0. Since char(ℂ) = 0, we have x = 0. -/
215theorem pauli_exclusion :
216 ∀ (state : Type*) (ψ : state → state → ℂ),
217 (∀ a b, ψ a b = -(ψ b a)) → (∀ a, ψ a a = 0) := by
218 intro state ψ antisym a
219 have heq : ψ a a = -(ψ a a) := antisym a a
220 -- x = -x in ℂ implies x = 0 (since char ℂ = 0)
221 -- Algebraic proof: x = -x → x - x = -x - x → 0 = -2x → x = 0
222 have h2 : (2 : ℂ) ≠ 0 := two_ne_zero
223 -- ψ + ψ = ψ + (-ψ) = 0
224 have hsum : ψ a a + ψ a a = 0 := by
225 nth_rewrite 2 [heq]
226 exact add_neg_cancel (ψ a a)
227 have h2x : (2 : ℂ) * ψ a a = 0 := by rw [two_mul]; exact hsum
228 exact (mul_eq_zero.mp h2x).resolve_left h2
229
230/-! ## Connection to 8-Tick Ledger -/
231