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arXiv:2604.23298 · detector doi_compliance · cross_source · 2026-05-19 23:16:33.348703+00:00

critical doi_compliance unresolvable_identifier

Identifier '10.5072/zenodo.484495' is syntactically valid but the DOI registry (doi.org) returned 404, and Crossref / OpenAlex / internal corpus also have no record. The cited work could not be located through any authoritative source.

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Evidence text

Due to Bose-Einstein statistics, the isospin for the subsystem of two identityDmesons can be ony 1. In the expression, we have already set the total isospin toT= 1 2. Considering the spin quantum numbers:J(D) = 0and J(K) = 0, the spin partS JM of theDDKsystem is trivial. ForJ(D ∗) = 1, the spin partS JM of theD ∗D∗Ksystem can be expressed as SJM =S 00 = 1√ 3 |1−1⟩+ 1√ 3 |−1 1⟩ − 1√ 3 |0 0⟩,(21) where the coefficients in front of the states are Clebsch- Gordan (CG) coefficients. In the CMS frame, we rewrite the Schr ¨odinger equation in terms of Jacobi coordinates and expand the coordinate-space wave function using two sets of Gaussian basis functions, ϕG nlm(rc)andψ G N LM(Rc), corresponding two Jacobi coor- dinates: Φc lL,Λ(rc,R c) = ϕG nlm(rc)ψG N LM(Rc) Λ , ϕG nlm(r) =N nlrle−νnr2 Ylm(ˆr), ψG N LM(R) =N N LRLe−λN R2 YLM( ˆR), Nnl = 2l+2(2νn)l+ 3 2 √π(2l+ 1)!! ! 1 2 ,(22) whereY LM is the spherical harmonic function. Three sets of Jacobi coordinates are considered in our system, as two of them illustrated in Fig. 2. It is clear that the basis in- volves powers of coordinates for nonzerolandL, which in- troduces considerable numerical challenges in the computa- tion of matrix elements. Since the contribution from higher partial waves is expected to be much smaller than that of the S-wave, in this work, we only consider the ground state of the three-body system. To maximize the numerical accuracy, the Gaussian param- eters are chosen in geometric progression: λN = 1/R2 N , R 

Evidence payload

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  "doi": "10.5072/zenodo.484495",
  "raw_excerpt": "Due to Bose-Einstein statistics, the isospin for the subsystem of two identityDmesons can be ony 1. In the expression, we have already set the total isospin toT= 1 2. Considering the spin quantum numbers:J(D) = 0and J(K) = 0, the spin partS JM of theDDKsystem is trivial. ForJ(D \u2217) = 1, the spin partS JM of theD \u2217D\u2217Ksystem can be expressed as SJM =S 00 = 1\u221a 3 |1\u22121\u27e9+ 1\u221a 3 |\u22121 1\u27e9 \u2212 1\u221a 3 |0 0\u27e9,(21) wh",
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