A short proof of Grinshpon's theorem
classification
🧮 math.RA
keywords
grinshponinvertibleproofshortcommutativegiveprovedresult
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Grinshpon has proved that if $S$ is a commutative subring of a ring $R$ and $A\in M_n(S)$ is invertible in $M_n(R)$, then $det(A)$ is invertible in $R$. We give a very short proof of the result.
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