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arxiv: 1211.6323 · v1 · pith:HSLJHFRAnew · submitted 2012-11-27 · 🧮 math.RA · math.GR

Ring coproducts embedded in power-series rings

classification 🧮 math.RA math.GR
keywords alphainjectiveamalgringrightsomethenarticle
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Let $R$ be a ring (associative, with 1), and let $R<< a,b>>$ denote the power-series $R$-ring in two non-commuting, $R$-centralizing variables, $a$ and $b$. Let $A$ be an $R$-subring of $R<< a>>$ and $B$ be an $R$-subring of $R<< b>>$, and let $\alpha$ denote the natural map $A \amalg_R B \to R<< a,b>>$. This article describes some situations where $\alpha$ is injective and some where it is not. We prove that if $A$ is a right Ore localization of $R[a]$ and $B$ is a right Ore localization of $R[b]$, then $\alpha$ is injective. For example, the group ring over $R$ of the free group on $\{1+a, 1+b\}$ is $R[ (1+a)^{\pm 1}] \amalg_R R[ (1+b)^{\pm 1}]$, which then embeds in $R<< a,b>>$. We thus recover a celebrated result of R H Fox, via a proof simpler than those previously known. We show that $\alpha$ is injective if $R$ is \textit{$\Pi$-semihereditary}, that is, every finitely generated, torsionless, right $R$-module is projective. The article concludes with some results contributed by G M Bergman that describe situations where $\alpha$ is not injective. He shows that if $R$ is commutative and $\text{w.gl.dim\,} R \ge 2$, then there exist examples where the map $\alpha' \colon A \amalg_R B \to R<< a>>\amalg_R R<< b>>$ is not injective, and hence neither is $\alpha$. It follows from a result of K R Goodearl that when $R$ is a commutative, countable, non-self-injective, von Neumann regular ring, the map $\alpha"\colon R<< a>>\amalg_R R<< b>> \to R<< a,b>>$ is not injective. Bergman gives procedures for constructing other examples where $\alpha"$ is not injective.

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