Solution of the strong CP problem
classification
✦ hep-ph
keywords
eithermixingonlyquarksstrongarisesavoidingbi-doublet
read the original abstract
I put forward an SU(2)_L x SU(2)_R x U(1) model in which spontaneously broken parity symmetry makes it that strong CP violation only arises at three-loop level. All leptons and up-type quarks are in doublets either of SU(2)_L or of SU(2)_R, but there are singlet down-type quarks. A bi-doublet of scalars is introduced which has only one component with non-vanishing expectation value, thereby avoiding W_L-W_R mixing. The scalar potential is such that scalar-pseudoscalar mixing does not occur either.
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