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On amenability and groups of measurable maps

Functional Analysis · Submitted 1 Jan 2017

abstract compiled · 2026-09-23 · no language-model review

The authors' main claim We show that if $G$ is an amenable topological group, then the topological group $L^{0}(G)$ of strongly measurable maps from $([0,1],\lambda)$ into $G$ endowed with the topology of convergence in measure is whirly amenable, hence extremely amenable.

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arXiv ID1701.00281 (version 2)
Pith IDYEHWDJFO, Pith's permanent record of this paper and its review
CitationFriedrich Martin Schneider, Vladimir G. Pestov. "On amenability and groups of measurable maps." arXiv:1701.00281 (2017). https://pith.science/paper/YEHWDJFO
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arXiv listing abstract v2. Results and the main claim are underlined; .

We show that if $G$ is an amenable topological group, then the topological group $L^{0}(G)$ of strongly measurable maps from $([0,1],\lambda)$ into $G$ endowed with the topology of convergence in measure is whirly amenable, hence extremely amenable. Conversely, we prove that a topological group $G$ is amenable if $L^{0}(G)$ is.

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#sentencerolethe authors' own workstates the main conclusionstrength
s0 We show that if $G$ is an amenable topological group, then the topological group $L^{0}(G)$ of strongly measurable maps from $([0,1],\lambda)$ into $G$ endowed with the topology of convergence in measure is whirly amenable, hence extremely amenable. result 0.99 0.95 0.61 asserted 1.00
s1 Conversely, we prove that a topological group $G$ is amenable if $L^{0}(G)$ is. result 0.99 0.93 0.30 asserted 1.00

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Original abstract

We show that if $G$ is an amenable topological group, then the topological group $L^{0}(G)$ of strongly measurable maps from $([0,1],\lambda)$ into $G$ endowed with the topology of convergence in measure is whirly amenable, hence extremely amenable. Conversely, we prove that a topological group $G$ is amenable if $L^{0}(G)$ is.

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