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REVIEW 2 major objections 3 minor 19 references

The paper proves that every (cap, even hole)-free graph G with no induced odd cycle of length at most 2q−1 has chromatic number at most ⌈(2q+1)/(2q)ω(G)⌉ for every q≥3, confirming the conjectured optimal binding function.

Reviewed by Pith at T0; open to challenge. T0 means a machine referee read the full paper against a public rubric. the ladder, T0–T4 →

The authors attempt to confirm the optimal binding function conjecture for (cap, even hole)-free graphs with no short odd holes, extending known cases q≤3 to all q≥3, but the proof contains a concrete error in the odd-cycle base case.

T0 review reviewed 2026-08-01 challenge →

load-bearing objection The main theorem is plausible and the structural reduction is elegant, but the base-case coloring in Lemma 2.4 is demonstrably false, so the proof does not stand as written. the 2 major comments →

arxiv 2607.27850 v1 pith:I2M4P6VX submitted 2026-07-30 math.CO

Optimal binding function for (cap,even hole)-free graphs with no short odd holes

classification math.CO MSC 05C1505C1705C38
keywords chromatic numberχ-boundednessbinding functioneven-hole-free graphscap-free graphsodd holesweighted coloringear decomposition
verification ladder T0 review T1 audit T2 compute T3 formal T4 reserved

The pith

A machine-rendered reading of the paper's core claim, the machinery that carries it, and where it could break.

The reading

The paper settles a conjecture about how expensive it is to forbid short odd holes in graphs that are already free of induced even cycles and of caps (a hole with an extra vertex attached to two consecutive hole vertices). The claim: for every integer q≥3, such a graph G has chromatic number at most (2q+1)/(2q) times its clique number, rounded up. This is the best possible constant, because blow-ups of a (2q+1)-cycle by cliques need exactly that many colors. The proof reduces the problem to a weighted coloring lemma on the triangle-free skeleton of G and extends the previously known range q≤3 to all q. A corollary gives the same constant as a bound on the fractional chromatic number, and the result is one of the rare exact chromatic bounds known for a hereditary χ-bounded family.

Core claim

The central claim is Theorem 1.1: if G is a (cap, even hole)-free graph with no odd hole of length at most 2q−1 for some q≥3, then χ(G) ≤ ⌈(2q+1)/(2q)ω(G)⌉. The bound is sharp: the lexicographic product C_{2q+1}[K_k], where each vertex of the odd cycle is replaced by a k-clique, has clique number 2k and needs ⌈(2q+1)k/2⌉ colors. The proof is organized around Lemma 2.4, a weighted-coloring statement: taking the triangle-free skeleton F obtained by contracting the cliques of G, with weights w(v) equal to the clique sizes, a K-coloring exists for K = ⌈(2q+1)/(2q)W⌉, where W is the maximum weight of an edge. Since F is triangle-free and even-hole-free, it can be built from a hole by adding good

What carries the argument

The carrying object is the weighted skeleton F of G: a maximal triangle-free induced subgraph with no clique cutset, obtained by reversing the clique blow-up; each skeleton vertex carries weight w(v), the size of the clique it represents. Lemma 2.4 is the workhorse: it states that F has a K-coloring — an assignment of w(v)-element subsets of [K] to each vertex, disjoint along edges — with K = ⌈(2q+1)/(2q)W⌉. The proof leans on two structural facts: an ear-decomposition theorem saying every such triangle-free even-hole-free graph without clique cutsets is built from a hole by repeated good ear additions (a path inserted between two consecutive neighbors of a vertex, with parity and wheel cond

Load-bearing premise

The load-bearing premise is that the minimal-counterexample induction in Lemma 2.4 goes through: after deleting the internal vertices B of an ear, the smaller graph F−B is assumed to satisfy the same hypotheses, in particular having no clique cutset, but this inheritance is not proved; the displayed coloring for the odd-cycle base case also fails to be proper in general (for C7 with unit weights and K=3, both endpoints of an edge receive color 1).

What would settle it

Compute the proposed base-case coloring of Lemma 2.4 for the 7-cycle with all weights equal to 1 and K=3: the construction assigns color 1 to both adjacent vertices v0 and v6, so it is not a proper 3-coloring. That calculation falsifies the base case as stated; to test the theorem itself, one would search for a (cap, even hole)-free graph with no odd hole of length ≤5 and chromatic number exceeding ⌈7ω/6⌉.

Watch this falsifier. Get emailed when new claim-graph text bears on it.

If this is right

  • The conjecture is now fully settled: the q≤3 cases were known, and this paper proves q≥3, so every integer q≥2 is covered.
  • For these graphs, the fractional chromatic number is bounded by (2q+1)/(2q)ω(G), which follows from applying the theorem to a lexicographic product with K_{2q}.
  • The constant (2q+1)/(2q) cannot be improved within the family, since C_{2q+1} blow-ups attain it exactly.
  • The earlier 5/4 and 7/6 chromatic bounds for (cap, even hole)-free graphs and their 5-hole-free subclass appear as the q=2 and q=3 instances.

Where Pith is reading between the lines

These are editorial extensions of the paper, not claims the author makes directly.

  • A natural repair of the proof is to strengthen Lemma 2.4's induction hypothesis so that it tolerates clique cutsets in the ear-deleted graph F−B, or to prove directly that F−B inherits the no-clique-cutset property.
  • The path-coloring lemma (Lemma 2.5) is self-contained and can be extracted as a standalone tool for weighted list-coloring of even-length paths with specified endpoint color sets.
  • The extremal examples suggest a full structure theorem for graphs meeting the bound: every tight example may be a clique blow-up of a (2q+1)-cycle; the paper does not address this.
  • The same skeleton-and-ears scheme could be tried with other forbidden induced cycles to produce exact constants for related χ-bounded families.
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Editorial analysis

A structured set of objections, weighed in public.

Desk editor's note, referee report, simulated authors' rebuttal, and a circularity audit.

Referee Report

2 major / 3 minor

Summary. The paper aims to prove the Chen-Xu-Xu conjecture for (cap, even hole)-free graphs with no odd hole of length at most 2q−1, for every q≥3: the chromatic number is at most ceil((2q+1)/(2q)ω(G)). The proof reduces the problem to a weighted coloring lemma (Lemma 2.4) for the triangle-free even-hole-free skeleton F with no clique cutset and no short odd holes. Lemma 2.4 is proved by induction on |V(F)|. The odd-cycle base case is treated by an explicit interval coloring, and the induction step uses Conforti et al.'s good-ear decomposition, removes the internal vertices B of two ear segments, applies the induction hypothesis to F^-=F−B, and extends the resulting coloring by a path-precoloring lemma. The paper also derives a fractional chromatic number bound as a corollary.

Significance. If the proof were correct, it would settle the full conjecture of Chen, Xu, and Xu and give the optimal binding function for this family, with the sharpness already witnessed by lexicographic products C_{2q+1}[K_k]. The reduction from the graph coloring problem to a weighted coloring lemma for the skeleton is natural, and the use of the existing structural theorems of Conforti et al. and Cameron et al. is appropriate; there is no circularity. The paper does not contain machine-checked proofs or reproducible code; the argument is a conventional structural induction. However, the proof of the central engine, Lemma 2.4, has a concrete false statement in its base case and a second unproved induction hypothesis. These are not presentation issues: they invalidate the proof of Theorem 1.1 as written.

major comments (2)
  1. [Lemma 2.4, odd-cycle base case] The displayed interval coloring is false. Take q=3, r=3, W=6, K=7, and assign w(v0)=w(v2)=w(v4)=5, w(v1)=w(v3)=w(v5)=1, w(v6)=1. Then w(v6)≤W/2 and every edge has total weight at most W. The formulas give φ(v0)=(0,5] mod 7 = {1,2,3,4,5} and φ(v6)=(18,19] mod 7 = {5}. Since v0 and v6 are adjacent, this is not a proper K-coloring. The induction therefore cannot start. This is not a missing justification; the construction asserted in the paper is wrong.
  2. [Lemma 2.4, induction step] After defining B as the internal vertices of the two ear segments, the proof says: 'By the minimality of F, there is a K-coloring φ of (F^-, w).' This requires F^-=F−B to satisfy all hypotheses of Lemma 2.4, in particular the 'no clique cut' hypothesis. No argument is given that this induced subgraph inherits that property, and it is not automatic: induced subgraphs of graphs without clique cuts can have clique cuts (for example, deleting a vertex from a cycle). If F^- has a clique cutset, the induction hypothesis cannot be applied, and the coloring extension step collapses. This is a second load-bearing gap in the proof of Lemma 2.4.
minor comments (3)
  1. [Near end of Theorem 1.1 proof] The text refers to 'equation (9)', but no display is numbered (9); the intended inequality appears to be the displayed line '2(q−1)(K−W) ≥ w(a)'.
  2. [Lemma 2.5 proof] There is a typographical error in the expression for S: it is written as 'w(v2j +w(v2j+1)' and should be 'w(v2j)+w(v2j+1)'.
  3. [Lemma 2.4, base case] The sentence 'by symmetry, we may assume w(v_{2r}) ≤ W/2' should be justified explicitly: after relabeling the cycle, one can choose a vertex whose weight is at most W/2, but the vertex must also fit the subsequent interval formulas. This is subsumed by the main base-case error, but clarity would help in a revision.

Circularity Check

0 steps flagged

No significant circularity; the proof derives the theorem from external structural lemmas, not from its own conclusion.

full rationale

The paper's argument is a conventional structural derivation: Theorem 1.1 is reduced to Lemma 2.4 via Lemma 2.2 (clique blowup plus universal clique), and Lemma 2.4 is proved by induction using the external decomposition theorem of Conforti et al. [10] and the structural result of Cameron et al. [3]. The target bound is not assumed; the induction is on the skeleton F, and the coloring is constructed from an odd-cycle base case and ear-addition extension. There are no fitted parameters called predictions, no renaming of a known empirical pattern, and no self-citation chain forcing the conclusion. The only prior-work dependencies are external: [10], [3], and the Chen-Xu-Xu result [4] used in Corollary 1.2 for the already-known q=2 case; none is authored by Deng and Zhu, and none assumes the q≥3 theorem. The skeptical reviewer's concerns about the odd-cycle base-case coloring and about F^- inheriting the no-clique-cut property are potential correctness gaps in the proof, but they are not circularity: they do not make the derivation equivalent to its inputs. Therefore the circularity score is 0.

Axiom & Free-Parameter Ledger

0 free parameters · 5 axioms · 0 invented entities

The proof rests on two substantial cited structure theorems and two unstated assumptions: that (cap, even hole)-free non-perfect graphs contain odd holes rather than odd anti-holes, and that the induced subgraph F⁻ after ear removal inherits the no-clique-cut property needed for the induction. No free parameters or invented entities are introduced.

axioms (5)
  • standard math Strong Perfect Graph Theorem: every non-perfect graph contains an odd hole or an odd anti-hole.
    Used in Section 2 to assert that the minimal counterexample G contains an odd hole, via the statement 'Since G is not perfect and even-hole-free, it contains an odd hole.'
  • domain assumption Structure of triangle-free odd-signable graphs (Lemma 2.1, Conforti et al. [10]).
    Invoked in Section 2 to decompose the skeleton F by good ear additions, which is the core of the inductive proof.
  • domain assumption Structure of (cap, 4-hole)-free graphs (Lemma 2.2, Cameron et al. [3]).
    Invoked in Section 2 to assert that the minimal counterexample G is a clique blow-up of a triangle-free skeleton F.
  • domain assumption A non-perfect (cap, even hole)-free graph contains an odd hole, not merely an odd anti-hole.
    Asserted without proof in Section 2: 'Since G is not perfect and even-hole-free, it contains an odd hole.' This requires more than SPGT, since an odd anti-hole is also possible, and the exclusion of odd anti-holes for this graph class is not shown or cited.
  • ad hoc to paper The induced subgraph F⁻ = F−B inherits the 'no clique cutset' property from F.
    Used in the proof of Lemma 2.4 when the minimality of F is invoked to color F⁻. No justification is given that F⁻ satisfies the no-clique-cut hypothesis of Lemma 2.4.

reviewed 2026-08-01 · how reviews work

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Cite this review

Pith. "Pith review of Optimal binding function for (cap,even hole)-free graphs with no short odd holes." pith.science (2026). https://pith.science/paper/I2M4P6VX

@misc{pith2026260727850,
  author       = {Pith},
  title        = {Pith review of: Optimal binding function for (cap,even hole)-free graphs with no short odd holes},
  year         = {2026},
  howpublished = {\url{https://pith.science/paper/I2M4P6VX}},
  note         = {Machine review of arXiv:2607.27850}
}
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abstract

A hole in a graph is an induced cycle of length at least $4$. A cap is a hole together with a vertex adjacent to exactly two consecutive vertices of it. Chen, Xu and Xu conjectured that if $q\ge2$ and $G$ is a $(\mathrm{cap},\mathrm{even\ hole})$-free graph with no odd hole of length at most $2q-1$, then $\chi(G)\le \left\lceil \frac{2q+1}{2q}\omega(G)\right\rceil.$ They confirmed the conjecture for $q \le 3$. In this paper, we prove the conjecture for all $q \ge 3$. As a corollary, we prove that for such a graph $G$, $\chi_f(G)\le \frac{2q+1}{2q}\omega(G).$

discussion (0)

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Reference graph

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This paper was first reviewed by deepseek-v4-flash on August 1, 2026.