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On divergence related to Riemann--von Mangoldt's explicit formula of the prime-counting function

Number Theory · Submitted 2 Sep 2026

Pith's verdict: A clean, credible proof that the conventional zero-indexed Riemann–von Mangoldt formula diverges, with one imported estimate worth checking before publication.

T0 · AI review

How this review was made: An AI referee (deepseek/deepseek-v4-flash) read the paper on September 8, 2026 and answered a fixed list of questions about it. T0 is the starting level every paper gets. The levels describe how deeply Pith has checked the paper, never the authors.

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arXiv ID2609.02713 (version 2)
Pith IDKH3JUSLC, Pith's permanent record of this paper and its review
CitationHarald Grobner. "On divergence related to Riemann--von Mangoldt's explicit formula of the prime-counting function." arXiv:2609.02713 (2026). https://pith.science/paper/KH3JUSLC
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Referee report
The paper

The paper claims

The paper proves that the partial sums over non-trivial zeros in the Riemann–von Mangoldt explicit formula are unbounded, so the series diverges and the formula as usually stated is not valid.

The reading

The paper challenges the widely used Riemann–von Mangoldt explicit formula for the prime-counting function. It proves that, for every fixed x>1 and any exponent θ less than Riemann's constant Θ, the partial sum ΣR_T(x) over non-trivial zeros ordered by increasing imaginary part is not O(T^θ). Consequently, the limit superior of |ΣR_T(x)| is infinite and the series diverges. This means that the expression ∑_ρ R(x^ρ) in the conventional ordering is not a well-defined complex number and the identity π₀(x)=R(x)−∑_ρ R(x^ρ) cannot hold with that summation. The argument also shows that the contribution of the trivial zeros diverges, further undermining the standard form of the formula.

What carries the argument

The key machinery is the auxiliary function P_A(t) = ∫_1^t log(y/(2π log x)) Re(ERi(−A+iy)) dy and a contour integral decomposition that relates ΣR_T(x) to P_A(log x T). The growth of P_A is controlled by poles of a truncated Mellin transform at the non-trivial zeros of ζ(s); Proposition 1.13 shows P_A(t) cannot be O(t^θ) for θ < Re(ρ). The contour integral, using a choice of good ordinates where horizontal contributions vanish (Lemma 2.5), yields ΣR_T(x) = (1/(π log x)) P_A(log x T) + constant + o(1), transferring the growth obstruction to ΣR_T(x).

Extended reading notes

Core claim

The central discovery is that for each fixed x>1 and any θ<Θ (where Θ is the supremum of real parts of non-trivial zeros, called Riemann’s constant), the partial sum ΣR_T(x) = ∑_{0<|Im(ρ)|≤T} m_ρ ERi(ρ log x) is not O(T^θ). Hence limsup_{T→∞}|ΣR_T(x)|=∞, so the series diverges. This implies that the expression ∑_ρ R(x^ρ) in the conventional ordering is not a well-defined complex number and the identity π₀(x)=R(x)−∑_ρ R(x^ρ) cannot hold with that summation. The argument also extends to show the divergence of the contribution of the trivial zeros.

Load-bearing premise

The proof that the horizontal contour sides vanish (Lemma 2.5) depends on the estimate that ERi(z) decays faster than any power of log|z| uniformly in every fixed vertical strip as |Im z|→∞ (cited from [Ell25, Prop. 4.5.2]). If this estimate fails in the strip needed for the argument, the relation between ΣR_T(x) and P_A would not hold, and the contradiction would collapse.

Editorial extensions

If this is right

  • The standard explicit formula for π₀(x) as usually presented in textbooks and online sources would need to be revised; the sum over zeros in the conventional ordering is not convergent.
  • Numerical computations that rely on the truncated sum ΣR_T(x) as an approximation of π₀(x)−R(x) must be interpreted with caution; the limit does not exist.
  • The result underscores that the interchange of summation over n and over ρ in deriving the formula is invalid unless additional summability methods are specified.
  • The divergence of the trivial-zero contribution (Proposition 4.1) further shows that even the second sum in the formula does not converge in the usual sense.

Reading between the lines

Editorial extensions of the paper, not claims the author makes directly.

  • If the paper is correct, then any use of the formula π(x) = R(x) − ∑ R(x^ρ) in heuristic or asymptotic arguments must be understood as a formal identity only, not as a convergent series in the standard sense. This raises questions about many applications that implicitly assume convergence.
  • The proof isolates the imported estimate from Elliott (2025) as the most delicate external assumption; a verification or independent proof of that estimate would strengthen the conclusion.
  • The auxiliary function P_A and its growth obstruction may provide a new testable condition: if numerical experiments could compute P_A(t) to high t, they should see oscillations that do not decay like any power less than Θ.
  • The divergence result does not preclude the existence of a different summation order (e.g., summing over zeros grouped by real part) that yields convergence; that remains an open question.
Original abstract

An explicit formula for the prime-counting function $\pi(x)$, usually attributed to Riemann and von Mangoldt, is prominently stated as the equation $\pi(x)=R(x)-\sum_\rho R(x^\rho)$, where the sum runs over all zeros $\rho$ of the Riemann $\zeta$-function, the non-trivial ones being ordered by increasing absolute value of their imaginary parts and counted with multiplicity. This particularly entails the claim that the partial sums over the non-trivial zeros, $\Sigma R_T(x):=\sum_{0<|\Im m(\rho)|\le T} R(x^\rho)$ converge as ${T\to\infty}$. Writing $\Theta:=\sup\{\Re e(\rho):\ \zeta(\rho)=0,\ 0<\Re e(\rho)<1\},$ for what has recently been called ``Riemann's constant'', we prove that, for every fixed $x>1$ and every $\theta<\Theta$, the sums $\Sigma R_T(x)$ are not $O(T^\theta)$. As a consequence, $\limsup_{{T\to\infty}}|\Sigma R_T(x)|=\infty$ and $\sum_\rho R(x^\rho)$ diverges. We conclude the paper by showing that an adapted, but simpler strategy also gives the analogous result -- and hence divergence -- for the contribution of the trivial zeros to $\sum_\rho R(x^\rho)$. In both cases the exponent $\Theta$ is proved to be sharp.

The compiled record

The paper's own sentences, arranged, kept beside the review and separate from it. Each label is drawn from a closed vocabulary; the number beside it is the probability the classifier gave that label. Numbers in the tables are the authors', checked by code. No sentence in this record was written by a model.

Compiled by classifier-1.13.0 via TypeSafe API, question bank abstract-p1-20260923, 2026-09-23: 1 request, 4,702 input tokens.

What the abstract itself states, as probabilities: claims first 0.05 · states limitation 0.12 · human participants 0.01 · controlled comparison 0.02 · randomized assignment 0.01 · states quantitative result 0.73 · compares with prior results 0.27 · mentions code or data availability 0.01.

The abstract, sentence by sentence

arXiv listing abstract v1. Results and the main claim are underlined; .

An explicit formula for the prime-counting function $\pi(x)$, usually attributed to Riemann and von Mangoldt, is prominently stated as the equation $\pi(x)=R(x)-\sum_\rho R(x^\rho)$, where the sum runs over all zeros $\rho$ of the Riemann $\zeta$-function, the non-trivial ones being ordered by increasing absolute value of their imaginary parts and counted with multiplicity. This particularly entails the claim that the partial sums over the non-trivial zeros, $\Sigma R_T(x):=\sum_{0<|\Im m(\rho)|\le T} R(x^\rho)$ converge as ${T\to\infty}$. Writing $\Theta:=\sup\{\Re e(\rho):\ \zeta(\rho)=0,\ 0<\Re e(\rho)<1\},$ for what has recently been called ``Riemann's constant'', we prove that, for every fixed $x>1$ and every $\theta<\Theta$, the sums $\Sigma R_T(x)$ are not $O(T^\theta)$. As a consequence, $\limsup_{{T\to\infty}}|\Sigma R_T(x)|=\infty$ and $\sum_\rho R(x^\rho)$ diverges. We conclude the paper by showing that an adapted, but simpler strategy also gives the divergence of the contribution of the trivial zeros to $\sum_\rho R(x^\rho)$.

background contribution method result interpretation main claim

What the classifier reports for each sentence. The number is the probability it gave the label.
#sentencerolethe authors' own workstates the main conclusionstrength
s0 An explicit formula for the prime-counting function $\pi(x)$, usually attributed to Riemann and von Mangoldt, is prominently stated as the equation $\pi(x)=R(x)-\sum_\rho R(x^\rho)$, where the sum runs over all zeros $\rho$ of the Riemann $\zeta$-function, the non-trivial ones being ordered by increasing absolute value of their imaginary parts and counted with multiplicity. background 1.00 0.04 0.03 asserted 1.00
s1 This particularly entails the claim that the partial sums over the non-trivial zeros, $\Sigma R_T(x):=\sum_{0<|\Im m(\rho)|\le T} R(x^\rho)$ converge as ${T\to\infty}$. background 0.95 0.06 0.05 asserted 0.99
s2 Writing $\Theta:=\sup\{\Re e(\rho):\ \zeta(\rho)=0,\ 0<\Re e(\rho)<1\},$ for what has recently been called ``Riemann's constant'', we prove that, for every fixed $x>1$ and every $\theta<\Theta$, the sums $\Sigma R_T(x)$ are not $O(T^\theta)$. result 0.95 0.94 0.21 asserted 1.00
s3 As a consequence, $\limsup_{{T\to\infty}}|\Sigma R_T(x)|=\infty$ and $\sum_\rho R(x^\rho)$ diverges. result 0.90 0.92 0.81 asserted 1.00
s4 We conclude the paper by showing that an adapted, but simpler strategy also gives the divergence of the contribution of the trivial zeros to $\sum_\rho R(x^\rho)$. result 0.86 0.95 0.07 asserted 1.00

What kind of paper the classifier reports this is: theoretical result 1.00 · evidence from proof or derivation 1.00.

What was examined, and what was not

sources read
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Every quoted sentence on this record is the authors'. Every label is from Pith's closed vocabulary, with the probability shown beside it. Every number in the measurements table is the authors', checked by code. Record as JSON

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Discussion

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