Pith. Sign in

REVIEW

A quantitative two-interval criterion for the Riemann hypothesis

Number Theory · Submitted 7 Nov 2026 · 8 references

Pith's verdict: A clean new equivalence for RH with subexponential supports, logically coherent but sketchy on a few estimates.

T0 · AI review

How this review was made: An AI referee (deepseek/deepseek-v4-flash) read the paper on November 10, 2026 and answered a fixed list of questions about it. T0 is the starting level every paper gets. The levels describe how deeply Pith has checked the paper, never the authors.

  1. T0 AI review An AI read the paper and answered a fixed list of questions.
  2. T1 Audit Automatic checks that the references and files the paper relies on exist and match.
  3. T2 Compute The paper's code or calculations re-run with the same results.
  4. T3 Formal statement The claims written out in a formal math language a computer can read.
  5. T4 Proof Those claims proved, and the proof checked by computer.

How Pith checks papers →

· 3 major objections · 5 minor · Ask about this paper · The compiled record · Read the full review →
Challenge this review Comment (0) Read on arXiv ↗
Cite ▾
arXiv ID2611.10726 (version 1)
Pith IDCFQVMBZY, Pith's permanent record of this paper and its review
CitationPayam Danesh. "A quantitative two-interval criterion for the Riemann hypothesis." arXiv:2611.10726 (2026). https://pith.science/paper/CFQVMBZY
Cite this reviewBibTeX for Pith's review of this paper
Claim paper

Why Pith says this

Highlight any text to comment on it.

Referee report
The paper

The paper claims

The Riemann hypothesis is equivalent to a Cauchy-Schwarz bound on test functions with subexponentially shrinking supports.

The reading

This paper tries to prove that the Riemann hypothesis (RH) can be reformulated as a concrete inequality involving the Cauchy-Schwarz norm of the Weil quadratic form evaluated on pairs of smooth test functions. If RH is true, then for every pair of functions supported on two short intervals that move far apart and shrink subexponentially, the normalized cross term is bounded by 1. If RH is false (a zero with real part greater than 1/2 exists), then the cross term grows exponentially at arbitrarily large separations, with an exponent that can be made arbitrarily close to the zero's horizontal displacement. The key advance is that the support intervals can be made extremely narrow (width decaying faster than any exponential) while still capturing the full force of RH. The resulting criterion pinpoints a uniform arithmetic inequality involving prime powers in a moving interval whose proof would settle RH.

What carries the argument

The central object is the normalized Weil cross term R(f,g)=|B(f,g)|/√(Q(f)Q(g)), where B is the Weil quadratic form summing over zeta zeros. The machinery that carries the argument is a smooth partition of unity that decomposes a fixed test function h into O(1/w(L)) pieces, each supported on an interval of width about w(L), and then applies the hypothesized bound on admissible pairs to the translates. The subexponential condition log(1/w(L))=o(L) makes the number of pieces subexponential in L, so that any exponential growth from a counterexample survives the summation. The pole obstruction in Lemma 3 uses the Laplace transform of the translated cross term to show that an exponential bound would force holomorphy in a half-plane contradicting a residue from a zero off the critical line.

Extended reading notes

Core claim

The paper establishes that the Riemann hypothesis is equivalent to the condition that for every real admissible pair of smooth functions (f,g) — supported respectively on [0,w(L)] and [L-w(L),L] with log(1/w(L))=o(L) — the normalized Weil cross term R(f,g) ≤ 1 for all sufficiently large L. If RH holds, Cauchy-Schwarz on the zero sequence gives the bound directly. If RH fails, a zero with real part β>1/2 forces the existence of pairs with R(f,g) > $e^{{ηL}}$ for any η < β-1/2, violating the bound. The proof combines a short-support positivity estimate (Lemma 1), a smooth partition procedure that transfers a bound on narrow-supported pairs to translates of a fixed function with a subexponential cost (Lemma 2), and a Laplace-transform pole argument showing that an exponential bound on the translated term would contradict the presence of an off-line zero (Lemma 3). The width condition log(1/w(L))=o(L) is essential: it ensures the partition cost remains subexponential, so the exponential violation from a false zero cannot be absorbed.

Load-bearing premise

The subexponential decay condition log(1/w(L))=o(L) on the support width is load-bearing: it ensures the number of partition pieces needed to translate a bound from narrow to wide functions grows subexponentially, so that an exponential violation from a false zero cannot be hidden by the partition cost.

Editorial extensions

If this is right

  • If the paper's equivalence is correct, proving RH becomes a single uniform arithmetic inequality: for all admissible pairs with subexponentially shrinking supports, the prime-power sum and the pole-integral combination in equation (36) must not exceed √(Q(f)Q(g)), with a constant gap that is uniform in L.
  • The reciprocal-width case w(L)=1/L is a concrete test case: one would need to show that for functions supported on intervals of length 1/L, the normalized cross term never exceeds 1.
  • Any computational or analytic method that verifies the inequality for a class of admissible pairs would immediately imply RH for that class; a single counterexample (R>1) at some large L would disprove RH.
  • The result shows that the Weil positivity criterion does not require full flexibility in support geometry — two widely separated, extremely narrow intervals suffice, which may simplify future numerical or analytic attacks on RH.
  • The paper's Lemma 2 gives a template for transferring bounds from narrow-supported pairs to much wider functions, with the subexponential cost controlled entirely by the width decay rate.

Reading between the lines

Editorial extensions of the paper, not claims the author makes directly.

  • If the equivalence holds, searching for a counterexample to RH could be replaced by searching for a pair (f,g) of the prescribed narrow-support form with R(f,g)>1. Since the supports are extremely short, such a search might be computationally tractable for moderate L, but the required L may be astronomically large before the exponential violation kicks in.
  • The width condition log(1/w(L))=o(L) includes slowly decaying widths like 1/L^a for any a>0, but excludes exponential decay w(L)=e^{-cL}. This suggests a potential sharpness: if w(L) decays exponentially, the partition cost becomes exponential and the argument fails; determining whether the equivalence still holds for such faster decay would require a different method.
  • The paper's arithmetic formulation (Section 5) expresses the cross term through prime powers in a moving interval. This connects the two-interval criterion to the distribution of primes in short intervals, and establishing the required bound may depend on deep results beyond current knowledge, such as strong forms of the prime number theorem in very short intervals.
  • The paper leaves the construction of a violating pair from a hypothetical zero non-constructive (only existence is proven). Developing an explicit algorithm to compute such a pair given the zero would make the criterion more operational for disproving RH.
Original abstract

We aim to study whether the Weil form can detect a zero of the Riemann zeta function away from the critical line using two functions with increasingly narrow, widely separated supports. We prove that the Riemann hypothesis is equivalent to the Cauchy-Schwarz inequality on every such pair at all sufficiently large separations, provided the component widths decrease subexponentially. A zero to the right of the critical line forces the normalized cross term to exceed an exponential at arbitrarily large separations, with any exponent smaller than the horizontal displacement of that zero. In particular, reciprocal-width intervals suffice. Our proof combines a short-support positivity estimate, a smooth partition of fixed test functions and a pole obstruction for a one-sided Laplace transform. We also express the cross term through prime powers in a moving multiplicative interval. The resulting criterion specifies a uniform arithmetic inequality whose proof would establish the Riemann hypothesis.

The compiled record

The paper's own sentences, arranged, kept beside the review and separate from it. Each label is drawn from a closed vocabulary; the number beside it is the probability the classifier gave that label. Numbers in the tables are the authors', checked by code. No sentence in this record was written by a model.

Compiled by classifier-1.13.0 via TypeSafe API, question bank abstract-p1-20260923, 2026-11-10: 1 request, 5,521 input tokens.

What the abstract itself states, as probabilities: claims first 0.04 · states limitation 0.39 · human participants 0.01 · controlled comparison 0.04 · randomized assignment 0.01 · states quantitative result 0.69 · compares with prior results 0.10 · mentions code or data availability 0.02.

The abstract, sentence by sentence

arXiv listing abstract v1. Results and the main claim are underlined; .

We aim to study whether the Weil form can detect a zero of the Riemann zeta function away from the critical line using two functions with increasingly narrow, widely separated supports. We prove that the Riemann hypothesis is equivalent to the Cauchy-Schwarz inequality on every such pair at all sufficiently large separations, provided the component widths decrease subexponentially. A zero to the right of the critical line forces the normalized cross term to exceed an exponential at arbitrarily large separations, with any exponent smaller than the horizontal displacement of that zero. In particular, reciprocal-width intervals suffice. Our proof combines a short-support positivity estimate, a smooth partition of fixed test functions and a pole obstruction for a one-sided Laplace transform. We also express the cross term through prime powers in a moving multiplicative interval. The resulting criterion specifies a uniform arithmetic inequality whose proof would establish the Riemann hypothesis.

background contribution method result interpretation main claim

What the classifier reports for each sentence. The number is the probability it gave the label.
#sentencerolethe authors' own workstates the main conclusionstrength
s0 We aim to study whether the Weil form can detect a zero of the Riemann zeta function away from the critical line using two functions with increasingly narrow, widely separated supports. contribution 0.70 0.34 0.04 unclear 0.47
s1 We prove that the Riemann hypothesis is equivalent to the Cauchy-Schwarz inequality on every such pair at all sufficiently large separations, provided the component widths decrease subexponentially. result 0.97 0.94 0.86 asserted 1.00
s2 A zero to the right of the critical line forces the normalized cross term to exceed an exponential at arbitrarily large separations, with any exponent smaller than the horizontal displacement of that zero. result 0.95 0.83 0.20 asserted 1.00
s3 In particular, reciprocal-width intervals suffice. result 0.67 0.78 0.05 asserted 0.97
s4 Our proof combines a short-support positivity estimate, a smooth partition of fixed test functions and a pole obstruction for a one-sided Laplace transform. method 1.00 0.93 0.03 asserted 1.00
s5 We also express the cross term through prime powers in a moving multiplicative interval. method 0.61 0.91 0.03 asserted 1.00
s6 The resulting criterion specifies a uniform arithmetic inequality whose proof would establish the Riemann hypothesis. interpretation 0.56 0.86 0.49 asserted 0.86

What kind of paper the classifier reports this is: theoretical result 1.00 · evidence from proof or derivation 1.00.

What was examined, and what was not

sources read
  • arXiv listing abstract v1
not examined
  • full text
  • figures and tables
  • references and citing sentences
  • relations to other papers
levels run
  • P abstract
not run
  • S sections
  • T body sentences
  • C citations
  • R cross-paper relations

Every quoted sentence on this record is the authors'. Every label is from Pith's closed vocabulary, with the probability shown beside it. Every number in the measurements table is the authors', checked by code. Record as JSON

Figures
Figure 1. shows the reciprocal-width geometry. The outer span determines the separation, whereas each diagonal energy is evaluated on one short interval
Figure 2. Analytic component widths L −1 , L −2 and exp  − √ L  for 2 ≤ L ≤ 25, plotted on a logarithmic vertical axis to illustrate three instances of Eq (12). 4 The criterion and quantitative violations A translated even test gives a Laplace transform whose poles retain the centered zeta zeros. This supplies the obstruction to the bound in Lemma 2. Lemma 3. We suppose z0 = ρ0 − 1/2 satisfies Rz0 > α ≥ 0. There is a real even h ∈ D such that Fh(t) := B (τth, h) fails to be O

Figures reproduced from arXiv:2611.10726 by the authors.

References

Discussion

Disagree with the review, or know something it missed? Leave a comment, highlight any passage above to comment on it, or challenge this review formally.