REVIEW
A quantitative two-interval criterion for the Riemann hypothesis
Number Theory · Submitted 7 Nov 2026 · 8 references
Pith's verdict: A clean new equivalence for RH with subexponential supports, logically coherent but sketchy on a few estimates.
T0 · AI review
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Referee report
The paper
The paper claims
The Riemann hypothesis is equivalent to a Cauchy-Schwarz bound on test functions with subexponentially shrinking supports.
The reading
What carries the argument
The central object is the normalized Weil cross term R(f,g)=|B(f,g)|/√(Q(f)Q(g)), where B is the Weil quadratic form summing over zeta zeros. The machinery that carries the argument is a smooth partition of unity that decomposes a fixed test function h into O(1/w(L)) pieces, each supported on an interval of width about w(L), and then applies the hypothesized bound on admissible pairs to the translates. The subexponential condition log(1/w(L))=o(L) makes the number of pieces subexponential in L, so that any exponential growth from a counterexample survives the summation. The pole obstruction in Lemma 3 uses the Laplace transform of the translated cross term to show that an exponential bound would force holomorphy in a half-plane contradicting a residue from a zero off the critical line.
Extended reading notes
Core claim
The paper establishes that the Riemann hypothesis is equivalent to the condition that for every real admissible pair of smooth functions (f,g) — supported respectively on [0,w(L)] and [L-w(L),L] with log(1/w(L))=o(L) — the normalized Weil cross term R(f,g) ≤ 1 for all sufficiently large L. If RH holds, Cauchy-Schwarz on the zero sequence gives the bound directly. If RH fails, a zero with real part β>1/2 forces the existence of pairs with R(f,g) > $e^{{ηL}}$ for any η < β-1/2, violating the bound. The proof combines a short-support positivity estimate (Lemma 1), a smooth partition procedure that transfers a bound on narrow-supported pairs to translates of a fixed function with a subexponential cost (Lemma 2), and a Laplace-transform pole argument showing that an exponential bound on the translated term would contradict the presence of an off-line zero (Lemma 3). The width condition log(1/w(L))=o(L) is essential: it ensures the partition cost remains subexponential, so the exponential violation from a false zero cannot be absorbed.
Load-bearing premise
The subexponential decay condition log(1/w(L))=o(L) on the support width is load-bearing: it ensures the number of partition pieces needed to translate a bound from narrow to wide functions grows subexponentially, so that an exponential violation from a false zero cannot be hidden by the partition cost.
Editorial extensions
If this is right
- If the paper's equivalence is correct, proving RH becomes a single uniform arithmetic inequality: for all admissible pairs with subexponentially shrinking supports, the prime-power sum and the pole-integral combination in equation (36) must not exceed √(Q(f)Q(g)), with a constant gap that is uniform in L.
- The reciprocal-width case w(L)=1/L is a concrete test case: one would need to show that for functions supported on intervals of length 1/L, the normalized cross term never exceeds 1.
- Any computational or analytic method that verifies the inequality for a class of admissible pairs would immediately imply RH for that class; a single counterexample (R>1) at some large L would disprove RH.
- The result shows that the Weil positivity criterion does not require full flexibility in support geometry — two widely separated, extremely narrow intervals suffice, which may simplify future numerical or analytic attacks on RH.
- The paper's Lemma 2 gives a template for transferring bounds from narrow-supported pairs to much wider functions, with the subexponential cost controlled entirely by the width decay rate.
Reading between the lines
- If the equivalence holds, searching for a counterexample to RH could be replaced by searching for a pair (f,g) of the prescribed narrow-support form with R(f,g)>1. Since the supports are extremely short, such a search might be computationally tractable for moderate L, but the required L may be astronomically large before the exponential violation kicks in.
- The width condition log(1/w(L))=o(L) includes slowly decaying widths like 1/L^a for any a>0, but excludes exponential decay w(L)=e^{-cL}. This suggests a potential sharpness: if w(L) decays exponentially, the partition cost becomes exponential and the argument fails; determining whether the equivalence still holds for such faster decay would require a different method.
- The paper's arithmetic formulation (Section 5) expresses the cross term through prime powers in a moving interval. This connects the two-interval criterion to the distribution of primes in short intervals, and establishing the required bound may depend on deep results beyond current knowledge, such as strong forms of the prime number theorem in very short intervals.
- The paper leaves the construction of a violating pair from a hypothetical zero non-constructive (only existence is proven). Developing an explicit algorithm to compute such a pair given the zero would make the criterion more operational for disproving RH.
Original abstract
We aim to study whether the Weil form can detect a zero of the Riemann zeta function away from the critical line using two functions with increasingly narrow, widely separated supports. We prove that the Riemann hypothesis is equivalent to the Cauchy-Schwarz inequality on every such pair at all sufficiently large separations, provided the component widths decrease subexponentially. A zero to the right of the critical line forces the normalized cross term to exceed an exponential at arbitrarily large separations, with any exponent smaller than the horizontal displacement of that zero. In particular, reciprocal-width intervals suffice. Our proof combines a short-support positivity estimate, a smooth partition of fixed test functions and a pole obstruction for a one-sided Laplace transform. We also express the cross term through prime powers in a moving multiplicative interval. The resulting criterion specifies a uniform arithmetic inequality whose proof would establish the Riemann hypothesis.
The compiled record
The paper's own sentences, arranged, kept beside the review and separate from it. Each label is drawn from a closed vocabulary; the number beside it is the probability the classifier gave that label. Numbers in the tables are the authors', checked by code. No sentence in this record was written by a model.
The abstract, sentence by sentence
We aim to study whether the Weil form can detect a zero of the Riemann zeta function away from the critical line using two functions with increasingly narrow, widely separated supports. We prove that the Riemann hypothesis is equivalent to the Cauchy-Schwarz inequality on every such pair at all sufficiently large separations, provided the component widths decrease subexponentially. A zero to the right of the critical line forces the normalized cross term to exceed an exponential at arbitrarily large separations, with any exponent smaller than the horizontal displacement of that zero. In particular, reciprocal-width intervals suffice. Our proof combines a short-support positivity estimate, a smooth partition of fixed test functions and a pole obstruction for a one-sided Laplace transform. We also express the cross term through prime powers in a moving multiplicative interval. The resulting criterion specifies a uniform arithmetic inequality whose proof would establish the Riemann hypothesis.
background contribution method result interpretation main claim
| # | sentence | role | the authors' own work | states the main conclusion | strength |
|---|---|---|---|---|---|
| s0 | We aim to study whether the Weil form can detect a zero of the Riemann zeta function away from the critical line using two functions with increasingly narrow, widely separated supports. | contribution 0.70 | 0.34 | 0.04 | unclear 0.47 |
| s1 | We prove that the Riemann hypothesis is equivalent to the Cauchy-Schwarz inequality on every such pair at all sufficiently large separations, provided the component widths decrease subexponentially. | result 0.97 | 0.94 | 0.86 | asserted 1.00 |
| s2 | A zero to the right of the critical line forces the normalized cross term to exceed an exponential at arbitrarily large separations, with any exponent smaller than the horizontal displacement of that zero. | result 0.95 | 0.83 | 0.20 | asserted 1.00 |
| s3 | In particular, reciprocal-width intervals suffice. | result 0.67 | 0.78 | 0.05 | asserted 0.97 |
| s4 | Our proof combines a short-support positivity estimate, a smooth partition of fixed test functions and a pole obstruction for a one-sided Laplace transform. | method 1.00 | 0.93 | 0.03 | asserted 1.00 |
| s5 | We also express the cross term through prime powers in a moving multiplicative interval. | method 0.61 | 0.91 | 0.03 | asserted 1.00 |
| s6 | The resulting criterion specifies a uniform arithmetic inequality whose proof would establish the Riemann hypothesis. | interpretation 0.56 | 0.86 | 0.49 | asserted 0.86 |
What was examined, and what was not
- arXiv listing abstract v1
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- relations to other papers
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Figures
Figures reproduced from arXiv:2611.10726 by the authors.
References
Discussion
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