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Could the $X(3915)$ and the $X(3930)$ Be the Same Tensor State?

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arxiv 1501.00879 v2 pith:6MB3SWHD submitted 2015-01-05 hep-ph hep-ex

classification hep-phhep-ex
keywords statedatagammatensordominancehelicity-2rightarrowsame
verification ladder T0 review T1 audit T2 compute T3 formal

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abstract

By using a combined amplitude analysis of the $\gamma\gamma\rightarrow D\bar{D}$ and $\gamma\gamma\rightarrow J/\psi\omega$ data, we demonstrate that the $X(3915)$, which is quoted as a $J^{PC}=0^{++}$ state in the Particle Data Group table, is favored by the data to be a $J^{PC}=2^{++}$ state appearing in both channels, which means that the $X(3915)$ and the $X(3930)$ can be regarded as the same $J^{PC}=2^{++}$ state. Meanwhile, the data also prefer a large helicity-0 contribution of this tensor resonance to the amplitudes instead of the helicity-2 dominance assumed by {\it BABAR}, which may indicate a sizable portion of non-$q\bar q$ components in this state. Identifying the $X(3915)$ with the $X(3930)$ and abandoning the helicity-2 dominance for this tensor state are helpful for the further understandings of the properties of this state and also of the mysterious "$XYZ$" charmoniumlike resonances.

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  1. Updated analysis of charmonium states in a relativized quark potential model

    hep-ph 2025-04 conditional novelty 5.0 of 10

    A recalibrated relativized quark model assigns chi_c1(4010), chi_c1(4274), chi_c0(4500), and chi_c0(4700) to conventional charmonium states and predicts chi_c0(2P) near 3851 MeV.

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