One hundred twenty-seven subsemilattices and planarity
Pith reviewed 2026-05-25 14:08 UTC · model grok-4.3
The pith
If a finite n-element semilattice has at least 127·2^{n-8} subsemilattices then it must be planar.
A machine-rendered reading of the paper's core claim, the machinery that carries it, and where it could break.
Core claim
Let L be a finite n-element semilattice. We prove that if L has at least 127·2^{n-8} subsemilattices, then L is planar. For n>8, this result is sharp since there is a non-planar semilattice with exactly 127·2^{n-8}-1 subsemilattices.
What carries the argument
The threshold function 127·2^{n-8} obtained by exhaustive enumeration of subsemilattices in finite cases, separating those semilattices whose Hasse diagrams are planar from those that are not.
If this is right
- Any semilattice whose subsemilattice count meets or exceeds the threshold has a crossing-free diagram.
- Non-planar semilattices are confined to having strictly fewer than 127·2^{n-8} subsemilattices when n exceeds 8.
- The extremal non-planar examples achieve exactly one less than the threshold count.
- The constant 127 encodes the maximal subsemilattice count attainable in the smallest non-planar base cases.
Where Pith is reading between the lines
- The same counting argument might be adapted to give computable certificates for planarity in software that enumerates subsemilattices.
- It remains open whether analogous numerical thresholds exist for other geometric properties such as outerplanarity or embeddability on the torus.
- The exponential factor 2^{n-8} suggests that the dominant contribution to subsemilattice growth comes from independent choices on a fixed-size core.
Load-bearing premise
The semilattice must be finite, because the proof enumerates and bounds the collection of all subsemilattices.
What would settle it
Exhibit a finite non-planar semilattice on n elements that possesses at least 127·2^{n-8} subsemilattices.
Figures
read the original abstract
Let $L$ be a finite $n$-element semilattice. We prove that if $L$ has at least $127\cdot 2^{n-8}$ subsemilattices, then $L$ is planar. For $n>8$, this result is sharp since there is a non-planar semilattice with exactly $127\cdot 2^{n-8}-1$ subsemilattices.
Editorial analysis
A structured set of objections, weighed in public.
Referee Report
Summary. The paper proves that any finite n-element semilattice with at least 127·2^{n-8} subsemilattices is planar, and shows the bound is sharp for n>8 via an explicit non-planar construction achieving exactly one fewer subsemilattice.
Significance. If the proof and construction hold, this supplies a sharp extremal threshold connecting subsemilattice enumeration to Hasse-diagram planarity in finite semilattices. The matching lower-bound example is a clear strength, as is the direct (non-asymptotic) nature of the result.
minor comments (1)
- The abstract and introduction should explicitly state the precise definition of 'planar semilattice' (Hasse diagram embeddable in the plane without crossings) to avoid any ambiguity for readers outside order theory.
Simulated Author's Rebuttal
We thank the referee for the positive assessment of our manuscript and the recommendation to accept. We appreciate the recognition of the direct, sharp nature of the extremal threshold relating subsemilattice counts to Hasse-diagram planarity.
Circularity Check
No significant circularity; direct proof and explicit construction
full rationale
The paper states a sharp extremal theorem for finite semilattices: a lower bound on the number of subsemilattices forces planarity of the Hasse diagram, with an explicit non-planar example achieving one fewer subsemilattice. The finiteness assumption is stated explicitly and is required for the counting argument. No equations, parameters, or claims reduce to self-definition, fitted inputs renamed as predictions, or load-bearing self-citations. The derivation consists of a combinatorial proof plus a concrete construction, both independent of the target statement.
Axiom & Free-Parameter Ledger
Reference graph
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discussion (0)
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