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Hypergeometric SLE: Conformal Markov Characterization and Applications

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arxiv 1703.02022 v4 pith:KVXX74H6 submitted 2017-03-06 math.PR

classification math.PR
keywords kappaprovedconformalhslepropertiesclassificationexistencegive
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abstract

This article pertains to the classification of pairs of simple random curves with conformal Markov property and symmetry. We give the complete classification of such curves: conformal Markov property and symmetry single out a two-parameter family of random curves---Hypergeometric SLE---denoted by hSLE$_{\kappa}(\nu)$ for $\kappa\in (0,4]$ and $\nu<\kappa-6$. The proof relies crucially on Dub\'edat's commutation relation [Dub07] and a uniqueness result proved in [MS16b]. The classification indicates that hypergeometric SLE is the only possible scaling limit of the interfaces in critical lattice models (conjectured or proved to be conformal invariant) in topological rectangles with alternating boundary conditions. We also prove various properties of hSLE: continuity, reversibility, target-independence, and conditional law characterization. As by-products, we give two applications of these properties. The first one is about the critical Ising interfaces. We prove the convergence of the Ising interface in rectangles with alternating boundary conditions. This result was first proved by Izyurov in [Izy15], but our proof is new which is based on the properties of hSLE. The second application is the existence of the so-called pure partition functions of multiple SLEs. Such existence was proved for $\kappa\in (0,8)\setminus \mathbb{Q}$ in [KP16], and it was later proved for $\kappa\in (0,4]$ in [PW17]. We give a new proof of the existence for $\kappa\in (0,6]$ using the properties of hSLE.

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  1. Connection probabilities in the double-dimer model -- the case of two connectivity patterns

    math-ph 2019-08 conditional novelty 5.0 of 10

    Using Grassmannian integrals, the double-dimer connection probability on a rectangle is shown to converge in the continuum to the known SLE4/CLE4 value (1-x)/(1+x).

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