Interpreting Bohm quantum potentials in Computing quantum waves exactly from classical action
Pith reviewed 2026-05-21 06:56 UTC · model grok-4.3
The pith
The Bohm quantum potential can be set to zero without loss of generality when constructing quantum waves from classical action using a Feynman-kernel initialization.
A machine-rendered reading of the paper's core claim, the machinery that carries it, and where it could break.
Core claim
The continuity p.d.e. and the Hamilton-Jacobi p.d.e., extended by the Bohm potential, are undisputed. However, the actual action and density solutions depend on their initialization at t = 0. In this work, this initialization is motivated by the Feynman kernel, which is fundamentally different from the standard initialization of the Madelung solution. This in turn leads to different action and density solutions, and explains why in one case the Bohm quantum potential disappears and in the other does not. The resulting overall wave, however, is independent of this computational initialization.
What carries the argument
The initialization at t=0 of the action and density, motivated by the Feynman kernel, which determines whether the Bohm quantum potential remains in the solution or vanishes while keeping the same final wave.
If this is right
- The proof of Lemma 3.1 extends directly to cases that include the Bohm potential explicitly.
- The Bohm quantum potential term can be assumed to be zero in the wave construction without loss of generality.
- The overall wave function remains the same regardless of whether the initialization makes the Bohm potential appear or disappear.
- Different choices of starting conditions for the partial differential equations lead to different intermediate solutions for action and density.
Where Pith is reading between the lines
- This approach suggests that computational paths in solving for quantum waves can vary based on starting assumptions without affecting the physical outcome.
- Similar initialization dependencies might appear in other derivations that connect classical mechanics to quantum mechanics.
- Testing this with specific solvable systems like the harmonic oscillator could verify if the final wave matches across initializations.
Load-bearing premise
The Feynman-kernel initialization at t=0 produces a valid quantum wave whose action and density can be directly compared to the standard Madelung initialization while preserving the same final wave function.
What would settle it
Compute the action and density explicitly for a simple quantum system using both the Feynman-kernel initialization and the standard Madelung initialization, then check whether the final wave functions are identical and whether the Bohm potential is zero in the first case.
read the original abstract
The recent arXiv posting [11], commenting on the paper [7], argues that the proof of Lemma 3.1 in [7] is missing the Bohm quantum potential [1, 2] of the Madelung p.d.e. [9]. This short technical note extends the proof of Lemma 3.1 to introduce a Bohm quantum potential explicitly, and then shows why this term can be assumed to be zero in the wave construction, without loss of generality. The continuity p.d.e. and the Hamilton-Jacobi p.d.e., extended by the Bohm potential, are undisputed. However, the actual action and density solutions depend on their initialization at t = 0. In [7], this initialization is motivated by the Feynman kernel [4], which is fundamentally different from the standard initialization of the Madelung solution [9]. This in turn leads to different action and density solutions, and explains why in one case the Bohm quantum potential disappears and in the other does not. The resulting overall wave, however, is independent of this computational initialization.
Editorial analysis
A structured set of objections, weighed in public.
Referee Report
Summary. This short technical note extends the proof of Lemma 3.1 from the authors' prior work [7] to explicitly include the Bohm quantum potential in the Hamilton-Jacobi equation. It argues that the term can nevertheless be set to zero without loss of generality because the t=0 initialization (motivated by the Feynman kernel) produces different action S and density ρ trajectories than the standard Madelung initialization, while the reconstructed wave function remains independent of that choice.
Significance. If the asserted independence of the final wave function is rigorously established, the note would clarify why the Bohm potential vanishes in the authors' computational construction while remaining consistent with the undisputed continuity and extended Hamilton-Jacobi PDEs, thereby addressing the comment on [7] and strengthening the claim that exact quantum waves can be obtained from classical action under the chosen initialization.
major comments (1)
- [section on initialization dependence] In the section on initialization dependence: the central claim that the resulting overall wave is independent of the computational initialization (thereby allowing the Bohm term to be assumed zero without loss of generality) is asserted but not demonstrated. No explicit steps, equations, or verification are supplied showing that the two distinct (S, ρ) solution pairs reconstruct identical ψ = √ρ exp(iS/ℏ) at t > 0, one trajectory carrying a nonzero Bohm term and the other not.
Simulated Author's Rebuttal
We thank the referee for the careful reading and for identifying the need for a more explicit demonstration in our technical note. The comment is well taken: while the independence of the final wave function is asserted, the current manuscript does not supply the step-by-step verification requested. We will revise the note to include this demonstration, thereby strengthening the argument that the Bohm term can be set to zero without loss of generality under the Feynman-kernel initialization.
read point-by-point responses
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Referee: In the section on initialization dependence: the central claim that the resulting overall wave is independent of the computational initialization (thereby allowing the Bohm term to be assumed zero without loss of generality) is asserted but not demonstrated. No explicit steps, equations, or verification are supplied showing that the two distinct (S, ρ) solution pairs reconstruct identical ψ = √ρ exp(iS/ℏ) at t > 0, one trajectory carrying a nonzero Bohm term and the other not.
Authors: We agree that the independence claim requires explicit verification rather than assertion alone. In the revised manuscript we will insert a short derivation in the initialization-dependence section. Let (S_M, ρ_M) denote the solution pair obtained from standard Madelung initial data, which carries a nonzero Bohm potential Q in the extended Hamilton–Jacobi equation. Let (S_F, ρ_F) denote the pair obtained from the Feynman-kernel initial data, for which Q vanishes identically. Both pairs satisfy the same continuity equation and the same extended Hamilton–Jacobi equation, but with different initial conditions at t = 0. Crucially, the initial wave functions constructed from each pair coincide: ψ(0) = √ρ(0) exp(i S(0)/ℏ) is identical and equals the initial condition implied by the Feynman kernel. Because the time-dependent Schrödinger equation is linear and possesses unique solutions for given initial data (under standard regularity assumptions), the reconstructed waves ψ_M(t) and ψ_F(t) must be identical for all t > 0. We will write the difference δψ = ψ_M − ψ_F, note that it satisfies the homogeneous Schrödinger equation with δψ(0) = 0, and conclude δψ ≡ 0. This explicit uniqueness argument will be added together with the relevant initial-condition equations. revision: yes
Circularity Check
Bohm term set to zero wlog via initialization motivated in authors' prior work [7]
specific steps
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self citation load bearing
[Abstract / initialization paragraph]
"In [7], this initialization is motivated by the Feynman kernel [4], which is fundamentally different from the standard initialization of the Madelung solution [9]. This in turn leads to different action and density solutions, and explains why in one case the Bohm quantum potential disappears and in the other does not. The resulting overall wave, however, is independent of this computational initialization."
The claim that the Bohm term may be assumed zero without loss of generality rests on the specific t=0 initialization introduced in the authors' own prior paper [7]. The asserted independence of the final wave ψ = √ρ exp(iS/ℏ) under that initialization is not independently verified against the extended PDEs here; it is taken as given by the earlier construction, making the 'wlog' step circular with respect to [7].
full rationale
The note extends Lemma 3.1 to include the Bohm term in the Hamilton-Jacobi PDE but then asserts this term can be dropped without loss of generality. The only justification offered is that the action and density solutions depend on t=0 initialization, and that the initialization chosen in [7] (motivated by the Feynman kernel) produces trajectories where the Bohm term vanishes while the final wave remains the same. This independence claim is not re-derived from the extended PDEs; it is inherited from the construction already defined in the authors' previous paper. The step therefore reduces the present argument to properties of that self-citation.
Axiom & Free-Parameter Ledger
axioms (2)
- domain assumption The continuity PDE and Hamilton-Jacobi PDE extended by the Bohm potential are the correct governing equations.
- domain assumption Initialization at t=0 from the Feynman kernel is a valid starting point for the action and density.
Reference graph
Works this paper leans on
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[10]
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[11]
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work page internal anchor Pith review Pith/arXiv arXiv 2026
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discussion (0)
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