REVIEW 1 major objections 5 minor 23 references
An inequality between finite analogues of rank and crank moments
T0 review · 1 major / 5 minor · reviewed 2026-08-14 · deepseek-v4-flash
Pith's one-line read For every size bound $N$ and every even $k$, the finite crank moment $M_{k,N}(n)$ strictly exceeds the finite rank moment $N_{k,N}(n)$ for all $n \geq 1$.
desk verdict A careful, dense proof of a natural open conjecture in partition theory; the machinery is borrowed but the result is new and the argument checks out. read the letter →
The pith
A machine-rendered reading of the paper's core claim, the machinery that carries it, and where it could break.
The reading
What carries the argument
The load-bearing object is the generating function identity of Theorem 2.5 for $\mu_{2k,N}(n) - \eta_{2k,N}(n)$, the difference of the finite symmetrized crank and rank moments. It expresses that difference as a finite sum over non-increasing sequences $N \geq n_k \geq \cdots \geq n_1 \geq 1$ of terms with manifestly nonnegative coefficients, so the difference is a nonnegative integer for every $n$. The second ingredient is the family of polynomials $g_j(m)=\prod_{i=0}^{j-1}(m^2-i^2)$ together with the positive integers $S^*(k,j)$, which rewrite ordinary $2k$-th moments as positive linear combinations of symmetrized moments. These two parts turn coefficient nonnegativity into the strict moment inequality.
What would settle it
Compute the finite moments directly from the definitions (1.9) and (1.10) for small values, say $N=2$, $k=2$, and $n=1,\dots,10$, and compare with the claim; a single $n$ with $M_{2,N}(n) \leq N_{2,N}(n)$ would refute the theorem. Alternatively, expand the right-hand side of (2.9) as a $q$-series to a chosen order and check that no coefficient is negative — the proof asserts none can be.
Extended reading notes
Core claim
The central discovery is the identity of Theorem 2.5: the generating function for the difference of the finite symmetrized crank and rank moments equals a single chain sum $$\sum_{N \geq n_k \geq \cdots \geq n_1 \geq 1} \frac{$q^{{n_1+\cdots+n_k}}$}{(1-$q^{{n_1}}$)^2 \cdots (1-$q^{{n_k}}$)^2 ($q^{{n_1+1}}$;q)_{N-n_1}},$$ which expands as a power series with nonnegative coefficients. Hence each coefficient $\mu_{2k,N}(n) - \eta_{2k,N}(n)$ is nonnegative. Using the finite analogue of the classical relations between moments and symmetrized moments — expressed through the positive integers $S^*(k,j)$ — the paper converts this coefficient nonnegativity into the strict inequality $M_{2k,N}(n) > N_{2k,N}(n)$ for every even order, and indeed shows the gap is at least $2\,\mathrm{spt}(n,N)$.
Load-bearing premise
The proof depends on a double limit in Proposition 5.1 where the expressions are divided by $(1-\rho_1)(1-\rho_2)$ and then $\rho_1, \rho_2$ are taken to $1$ inside factors that vanish at that limit; the paper invokes a limiting identity for this step without supplying a full formal justification, so if that limit is not valid the nonnegative-coefficient representation is not established.
Editorial extensions
If this is right
- For each fixed $N$, the finite gap $M_{2k,N}(n) - N_{2k,N}(n)$ is at least $2\,\mathrm{spt}(n,N)$, so the difference grows at least as fast as the finite smallest-parts function in $n$.
- The finite higher-order spt-function $\mathrm{spt}_k(n,N) := \mu_{2k,N}(n) - \eta_{2k,N}(n)$ is nonnegative for all $k,n,N$, and equals $\mathrm{spt}(n,N)$ when $k=1$.
- Letting $N \to \infty$ in the chain-sum identity recovers the classical identity for the difference of symmetrized crank and rank moments, and hence the classical inequality between the $2k$-th crank and rank moments.
- Because the coefficients $S^*(k,j)$ are positive, nonnegativity of the symmetrized differences implies nonnegativity of the ordinary moment differences for every even $k$, not just for the smallest order.
Reading between the lines
- The same positivity mechanism may yield a stronger lower bound for $M_{2k,N}(n)-N_{2k,N}(n)$ in terms of higher-order finite spt-functions, since the proof only uses the $j=1$ term of the symmetrized expansion.
- A natural test is to compute the ratio $(M_{2k,N}(n)-N_{2k,N}(n))/(2\,\mathrm{spt}(n,N))$ for small $N,k,n$; the paper's proof forces it to be at least $1$, and numerical values would show how sharp that bound is.
- If the double limit in Proposition 5.1 were justified as a formal power series identity in $q$ for all $N$ and $k$, the proof would hold without any convergence assumptions, and the same style of argument could be tried on other pairings of partition statistics.
- The chain sum in Theorem 2.5 resembles a count of marked chains and may admit a direct combinatorial interpretation for $\mathrm{spt}_k(n,N)$, mirroring the classical interpretation of higher-order spt-functions.
Signed reviews
Editorial analysis
A structured set of objections, weighed in public.
Referee Report
Summary. The paper proves Conjecture 1.2 from the authors' earlier work [15]: for every fixed natural number N and every even k ≥ 2, the finite analogue of the crank moment exceeds the finite analogue of the rank moment: M_{k,N}(n) > N_{k,N}(n) for all n ≥ 1. To do this, the authors define finite analogues of symmetrized rank and crank moments η_{k,N}(n) and μ_{k,N}(n), derive their generating functions (Theorems 2.2 and 2.4), and then prove a nonnegative-coefficient generating function for the difference μ_{2k,N}(n) − η_{2k,N}(n) (Theorem 2.5). The proof of Theorem 2.5 is built on an induction using Bailey's lemma (Proposition 5.1) together with two classical Bailey pairs. The final step links ordinary finite moments to symmetrized moments through Garvan's numbers S*(k,j), yielding the stronger bound M_{2k,N}(n) − N_{2k,N}(n) ≥ 2 spt(n,N) > 0. The paper is a direct finite analogue of Garvan's proof of the classical rank-crank moment inequality.
Significance. If the proof is accepted, the paper settles a conjecture from [15] and provides a finite/restricted analogue of Garvan's theorem, extending a well-known circle of ideas in partition theory. The main technical contribution, Theorem 2.5, is a finite analogue of Garvan's difference generating function and appears to be new. The arguments are explicit q-series manipulations: Theorems 2.2 and 2.4 are derived from known partial-fraction identities, and Proposition 5.1 is a genuine application of Bailey's lemma. The positivity conclusion is clean and yields a stronger statement than the conjecture itself, namely the lower bound in terms of spt(n,N). The main weakness is that a key limiting identity, Eq. (3.7), is quoted without proof; I verified it independently and found it correct, but the manuscript should supply a derivation or reference. There are also several small typographical errors. Overall, the result is worthy of publication once the missing justification is added.
major comments (1)
- [Section 3, Eq. (3.7)] The limit identity (3.7) is stated without proof or reference and is used in a load-bearing way in both the base case and the induction step of Proposition 5.1, specifically when the proof divides by (1−ρ1)(1−ρ2) and then lets ρ1,ρ2 → 1. The identity is true: writing a = 1/ρ1 = 1−u and b = 1/ρ2 = 1−v, each factor (1−q^j)(1−ab q^j)/((1−a q^j)(1−b q^j)) expands as 1 − uv q^j/(1−q^j)^2 + O(u^2 v, u v^2), which gives (3.7). However, the manuscript should provide this derivation or cite a source, and it should comment on the double limit at the points where the denominators (q/ρ1)_n(q/ρ2)_n vanish. As written, the proof of Proposition 5.1 is incomplete at a critical step, even though the gap is readily fixable.
minor comments (5)
- [Section 5, proof of Conjecture 1.2] The displayed generating function in the proof of Conjecture 1.2 reads (μ_{2t,N}(n)q^n − η_{2t,N}(n))q^n, which appears to be a typo; it should be (μ_{2t,N}(n) − η_{2t,N}(n))q^n.
- [Section 5, proof of Theorem 2.5] The sentence 'Divide both sides of (5.4) by (q)_N' refers to the unnumbered display in Corollary 5.4, not to equation (5.4) in Proposition 5.5. Please add a cross-reference or number the display in Corollary 5.4.
- [Section 5, Corollary 5.2] In the sentence 'Substituting the above Bailey pair in Theorem 5.1', the reference should be to Proposition 5.1, not Theorem 5.1.
- [Abstract and Introduction] There are several typographical slips, including 'conjectur ed' and 'c rank' in the abstract, and 'Garvan himself' in the first sentence; these should be corrected in a final revision.
- [Section 5, proof of Proposition 5.1] When the proof says 'letting ρ1 → 1, ρ2 → 1 and using (3.7)', it may help the reader to note explicitly that all sums are finite (since the indices are bounded by N), so the interchange of limit and summation is immediate.
Circularity Check
No circularity found; the conjecture is proved from explicit generating functions and standard Bailey-pair identities, not assumed or fitted.
full rationale
I walked the derivation chain from the finite moment definitions through the symmetrized generating functions to the final inequality. The finite analogues are taken as definitions from the authors' earlier paper [15], and the generating functions (3.1) and (3.4) are cited from that paper, but the conjectured inequality itself is never assumed. Theorems 2.2 and 2.4 derive the symmetrized rank and crank generating functions directly from these definitions using standard derivative manipulations. Proposition 5.1 is proved from Bailey's lemma rather than from the target inequality. Corollaries 5.2-5.4 substitute standard Bailey pairs into Proposition 5.1, and Theorem 2.5 follows by combining these identities with Theorems 2.2 and 2.4. The final step uses the nonnegative-coefficient form of the difference generating function and the positive coefficients S*(k,j), so no fitted parameter is renamed as a prediction and no uniqueness or ansatz is imported from prior work to force the conclusion. The only delicate point visible in the proof, the double-limit identity (3.7), is quoted without proof; that is an expository gap rather than a circular reduction, since the identity is a computational lemma independent of the conjecture and can be checked directly. Self-citations supply definitions and background material, not the central claim, so the proof is not circular.
Assumptions & free parameters
assumptions (6)
- standard math Bailey's Lemma (Theorem 3.1)
- standard math Well-known Bailey pairs (α_n, β_n) from Andrews's book [1, pp. 27-28]
- standard math Partial fraction identities (3.2) and (3.5) due to Andrews
- standard math Limiting identity (3.7) for the double limit of q-products
- standard math Garvan's polynomial basis relation x^{2n} = Σ_{k=1}^n S*(n,k) g_k(x) with S*(n,k) > 0
- domain assumption Symmetry NS1(m,n)=NS1(-m,n) and MS2(m,n)=MS2(-m,n), established in [15, p.9]
invented entities (2)
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Finite analogue of symmetrized rank moment η_{k,N}(n)
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Finite analogue of symmetrized crank moment μ_{k,N}(n)
Cite this review
Pith. "Pith review of An inequality between finite analogues of rank and crank moments." pith.science (2026). https://pith.science/paper/XWODG6RR
@misc{pith2026190808660,
author = {Pith},
title = {Pith review of: An inequality between finite analogues of rank and crank moments},
year = {2026},
howpublished = {\url{https://pith.science/paper/XWODG6RR}},
note = {Machine review of arXiv:1908.08660}
}
read the original abstract
The inequality between rank and crank moments was conjectured and later proved by Garvan himself in 2011. Recently, Dixit and the authors introduced finite analogues of rank and crank moments for vector partitions while deriving a finite analogue of Andrews' famous identity for smallest parts function. In the same paper, they also conjectured an inequality between finite analogues of rank and crank moments, analogous to Garvan's conjecture. In the present paper, we give a proof of this conjecture.
Reference graph
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