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Schoenberg's Problem on Positive Definite Functions
Functional Analysis · Submitted 19 Oct 1992
abstract compiled · 2026-09-23 · no language-model review
The authors' main claim If $n \ge 3$, $q>2$ and $\beta > 0$ then the function $\exp(-(|x_1|^q+|x_2|^q+\dots+|x_n|^q)^{\beta/q})$\ is not positive definite.
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The abstract, sentence by sentence
If $n \ge 3$, $q>2$ and $\beta > 0$ then the function $\exp(-(|x_1|^q+|x_2|^q+\dots+|x_n|^q)^{\beta/q})$\ is not positive definite. This result gives an answer to a question posed by I.J.~Schoenberg in 1938. This text is an authorized English translation of the paper published in Russian in Algebra and Analysis 3(1991), \#3, p.78--85.
background contribution method result interpretation main claim
| # | sentence | role | the authors' own work | states the main conclusion | strength |
|---|---|---|---|---|---|
| s0 | If $n \ge 3$, $q>2$ and $\beta > 0$ then the function $\exp(-(|x_1|^q+|x_2|^q+\dots+|x_n|^q)^{\beta/q})$\ is not positive definite. | result 1.00 | 0.84 | 0.95 | asserted 1.00 |
| s1 | This result gives an answer to a question posed by I.J.~Schoenberg in 1938. | interpretation 0.58 | 0.49 | 0.05 | asserted 1.00 |
| s2 | This text is an authorized English translation of the paper published in Russian in Algebra and Analysis 3(1991), \#3, p.78--85. | background 0.98 | 0.12 | 0.02 | asserted 1.00 |
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Original abstract
If $n \ge 3$, $q>2$ and $\beta > 0$ then the function $\exp(-(|x_1|^q+|x_2|^q+\dots+|x_n|^q)^{\beta/q})$\ is not positive definite. This result gives an answer to a question posed by I.J.~Schoenberg in 1938. This text is an authorized English translation of the paper published in Russian in Algebra and Analysis 3(1991), \#3, p.78--85.
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