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Are $N\bar\Omega$ bound states?

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arxiv 2004.12876 v2 pith:M2TGAANR submitted 2020-04-24 nucl-th hep-ph

classification nucl-thhep-ph
keywords omegastatesboundsystemsscatteringsystemattractionbetter
verification ladder T0 review T1 audit T2 compute T3 formal
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abstract

Inspired by the progress of the experimental search of the $N\Omega$ dibaryon by the STAR collaboration, we study $N\bar{\Omega}$ systems in the framework of quark delocalization color screening model. Our results show that the attraction between $N$ and $\bar{\Omega}$ is a little bit larger than that between $N$ and $\Omega$, which indicates that it is more possible for the $N\bar{\Omega}$ than the $N\Omega$ system to form bound states. The dynamic calculations state that both the $J^{P}=1^{+}$ and $2^{+}$ $N\bar{\Omega}$ systems are bound states. The binding energy of these two states are deeper than that of $N\Omega$ systems with $J^{P}=2^{+}$, and the $N\Omega$ system with $J^{P}=1^{+}$ is unbound. The calculation of the low-energy scattering phase shifts, scattering length and the effective range also supports the existence of the $N\bar{\Omega}$ bound states with $J^{P}=1^{+}$ and $2^{+}$. So the $N\bar{\Omega}$ states are better hexaquark states and stronger signals are expected in experiments.

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  1. Could $\bar{\Lambda}_c$ and $\Lambda_c$ form bound hadronic molecule with explicit $P-wave$ ?

    hep-ph 2026-07 conditional novelty 5.0 of 10

    P-wave Λ̄cΛc dibaryon states with J^PC = 0^-± and 1^-± are extracted at ~5.7–5.8 GeV, about 0.9 GeV above their constituent thresholds, so they are unlikely to be bound molecules.

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