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9 times 4 = 6 times 6: Understanding the quantum solution to the Euler's problem of 36 officers

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arxiv 2204.06800 v2 pith:OWAAHECR submitted 2022-04-14 quant-ph

9 times 4 = 6 times 6: Understanding the quantum solution to the Euler's problem of 36 officers

classification quant-ph
keywords officersquantumproblementangledeulersolutionstatestimes
verification ladder T0 review T1 audit T2 compute T3 formal T4 reserved
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The famous combinatorial problem of Euler concerns an arrangement of $36$ officers from six different regiments in a $6 \times 6$ square array. Each regiment consists of six officers each belonging to one of six ranks. The problem, originating from Saint Petersburg, requires that each row and each column of the array contains only one officer of a given rank and given regiment. Euler observed that such a configuration does not exist. In recent work, we constructed a solution to a quantum version of this problem assuming that the officers correspond to quantum states and can be entangled. In this paper, we explain the solution which is based on a partition of 36 officers into nine groups, each with four elements. The corresponding quantum states are locally equivalent to maximally entangled two-qubit states, hence each officer is entangled with at most three out of his $35$ colleagues. The entire quantum combinatorial design involves $9$ Bell bases in nine complementary $4$-dimensional subspaces.

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