Pith. sign in

REVIEW

Better Sample -- Random Subset Sum in 2^(0.255n) and its Impact on Decoding Random Linear Codes

Not yet reviewed by Pith; the record is open.

This paper has not been read by Pith yet. Machine review is queued; the pith claim, tier, and objections will appear here once it completes.

SPECIMEN: schema-true, not a live event

T0 review · schema-true

One-sentence machine reading of the paper's core claim.

pith:XXXXXXXX · record.json · timestamp

arxiv 1907.04295 v2 pith:QYJFCJXR submitted 2019-07-09 cs.DS cs.CR

Better Sample -- Random Subset Sum in 2^(0.255n) and its Impact on Decoding Random Linear Codes

classification cs.DS cs.CR
keywords algorithmrandomsubsetdecodingimprovesearchbestcodes
verification ladder T0 review T1 audit T2 compute T3 formal T4 reserved
0 comments
read the original abstract

We propose a new heuristic algorithm for solving random subset sum instances $a_1, \ldots, a_n, t \in \mathbb{Z}_{2^n}$, which play a crucial role in cryptographic constructions. Our algorithm is search tree-based and solves the instances in a divide-and-conquer method using the representation method. From a high level perspective, our algorithm is similar to the algorithm of Howgrave-Graham-Joux (HGJ) and Becker-Coron-Joux (BCJ), but instead of enumerating the initial lists we sample candidate solutions. So whereas HGJ and BCJ are based on combinatorics, our analysis is stochastic. Our sampling technique introduces variance that increases the amount of representations and gives our algorithm more optimization flexibility. This results in the remarkable and natural property that we improve with increasing search tree depth. Whereas BCJ achieves the currently best known (heuristic) run time $2^{0.291n}$ for random subset sum, we improve (heuristically) down to $2^{0.255n}$ using a search tree of depth at least $13$. We also apply our subset algorithm to the decoding of random binary linear codes, where we improve the best known run time of the Becker-Joux-May-Meurer algorithm from $2^{0.048n}$ in the half distance decoding setting down to $2^{0.042n}$.

discussion (0)

Sign in with ORCID, Apple, or X to comment. Anyone can read and Pith papers without signing in.