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Remarks on the uncertainty relations

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arxiv 1810.11462 v5 pith:JHN4KPNB submitted 2018-10-27 quant-ph gr-qchep-phphysics.pop-ph

classification quant-phgr-qchep-phphysics.pop-ph
keywords deltacdotuncertaintyrelationrelationsvectorscompleteeigenvectors
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abstract

We analyze general uncertainty relations and we show that there can exist such pairs of non--commuting observables $A$ and $B$ and such vectors that the lower bound for the product of standard deviations $\Delta A$ and $\Delta B$ calculated for these vectors is zero: $\Delta A\,\cdot\,\Delta B \geq 0$. We show also that for some pairs of non--commuting observables the sets of vectors for which $\Delta A\,\cdot\,\Delta B \geq 0$ can be complete (total). The Heisenberg, $\Delta t \,\cdot\, \Delta E \geq \hbar/2$, and Mandelstam--Tamm (MT), $ \tau_{A}\,\cdot \,\Delta E \geq \hbar/2$, time--energy uncertainty relations ($\tau_{A}$ is the characteristic time for the observable $A$) are analyzed too. We show that the interpretation $\tau_{A} = \infty$ for eigenvectors of a Hamiltonian $H$ does not follow from the rigorous analysis of MT relation. We show also that contrary to the position--momentum uncertainty relation, the validity of the MT relation is limited: It does not hold on complete sets of eigenvectors of $A$ and $H$.

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  1. Critical look at the time-energy uncertainty relations

    quant-ph 2019-08 conditional novelty 4.0 of 10

    The Mandelstam-Tamm and Heisenberg time-energy uncertainty relations are not universally valid because their derivation divides by a vanishing time derivative for eigenstates of energy or the observable.

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